Re: Reticles MOA/MRAD
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">Well I think it does matter because I am using a linear measurement, an inch, which I am familiar with, to make a correction on an known size target at a know distance.</div></div>Nope. Actually you are not doing that, you just think you are, probably because of a lack of experience. In reality you are adjusting by an angular unit of measurement and using inches to derive it. You could use centimeters, yards, meters or parsecs to do the same - with either Mils or MOA.
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">I am not trying to solve a range finding question, or estimate the distance to a target where the angular measurement comes into play. You are using long distances (837?) as examples where the numbers are very small and would in fact be very hard to see, but I think I can see 4.5" as easy/easier than you can see .1 Mill.</div></div> That’s like saying you can see 2.54” better than you can see one centimeter. No you can’t: It’s exactly the same thing. You are just calling it another name by expressing the same size using a different unit of measurement. The problem is that you are using a linear unit to describe an angular measurement, and that’s why your technique is wrong.
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">One more example and I'm done, if a shooter is shooting at 900YDS at a paper bulls eye target and bull is 10" edge to edge and the "9" ring is 20" edge to edge we all know he probably can't see his bullet hole in the target but when his spotter comes up and he sees the 5" spotter centered between the 9 ring and the edge of the bull then he knows that his correction is approx 7.5", a linear measurement, he then dials 3/4MOA (1MOA=1.047") an angular measurement, and makes his next shot before the wind changes.</div></div> Now you are arguing against your former position. You are assuming a square range, and an even-hundred-yard distance, and someone giving you corrections in inches. In that case you don’t need anything but a crosshair reticle because you are planning to dial your windage. But even then inches don’t matter. Because you are dialing in MOA or in Mils depending on which measurements your scope has.
Note that with regard to your above example a 5” spotter cannot be used to give an accurate 7.5” correction. I’ve even seen experienced instructors get this wrong. I’ll give you an example: I was at Storm Mountain a few years back and the task was for us to get our DOPE for 200 yards. The instructor had the students in the pitts put a 2” spotter in the hole after each bullet was fired to show the shooter his point of impact. At the end of the exercise the instructor asked if we all now have good data for 200. I replied that none of us did. You should have seen the look on his face. Why was no one zeroed at 200? Because he was using 2” spotting circles... Well, that and the fact that he didn’t know how much he didn’t know.<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">I can go get a ruler and show someone what an inch is,(IPHY) but you cannot get one for a Mill, and for most people an IPHY or a shooters MOA, 1/1, is close enough because at 1000 the error is only .47" and most cannot shoot that well, lol.</div></div>Again you are arguing against yourself: You won’t find a ruler in Mils because an inch is a linear unit and a Mil is not. That’s why there’s no such thing as an ‘Inch-dot Master’. You don’t make angular corrections with linear units any more than you measure drapery in Mils.
And it’s not ‘close enough’. Your error calculation is incorrect. It’s a 5% error. With a .308, the difference in point of impact on a 1000 yard shot between using MOA and IPHY adjustments is twenty inches. So, even if you limit your effective range to under 500 yards the difference is not to be ignored. <div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">An inch IS applicable and visible & simply understood by most people whereas a Mill or MRAD is not. Most people do not understand what a mill is and don't know how to use it. I'm curious, are you refering to the NATO Mill of which there are 6400 in a circle or the mathmatical mill of 6283?</div></div> There is only one scope which uses the 6400 Mil. It’s the Leupold M3A. Modern optics use 6283. <div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Trooper #40</div><div class="ubbcode-body">My examples are based on emperical data (real world experience) not mathmatical theory. Thats why NF makes moa scopes for me, to each his own</div></div>Your real-world experience is insufficient. There’s no difference between correct math and ‘real-world’ math; they are one and the same. Understanding the correct math will help you hit things at distance.
NF makes MOA scopes because they sell: To people who prefer them and to those who don’t understand Mils. Many people claim to be the former when the real reason is that they are also the latter. When I started the long-distance game it became important to me not to remain one of those people. I suggest that you strive to be able to use Mils and MOA interchangeably. That way you can work with anyone and will be able to explain either system to other people.