Peak of shot above ground vs ballistic calculations

rogerg12

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Minuteman
Dec 25, 2020
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Palm Harbor, FL
In the video about the recent 4.4M world record () the shooters said their shot went 2500 feet above the ground at its peak. But a guy in the comments corrected them and said the shot didn’t get anywhere near 2500 above the ground/target. Commenter said the gun was angled upward to shoot the bullet 2500 feet above the ground, but the bullet didn’t go that far. The commenter said that a 6.5 creedmoor shooting at 1000 feet will be angled 37 feet above the ground but the bullet only goes 8 feet above the ground. I don’t know if the commenter is right, but he sounded like he knew what he was talking about. Is he right?
 
For a 140gr 6.5 Creedmoor at 1000 yards, ~37 feet of total drop and an ~8 foot max ord is correct. As to the claims for 4.4 miles none of my calculators will go that far.
 
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Here is something close, 375, 3200fps 4000 yards

Screenshot 2022-12-08 at 1.52.07 PM.png


9371 Inches from 100, 65MILS so you can use that as a reference

I have shot to 4000 in New Mexico was estimated 1500ft above line of sight

24993438_10155941051627953_7545560666062332125_n.jpg
 
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OK. How does something drop 37 feet if it is only a max of 8 feet above the horizontal plane?
Because they are misunderstanding the comment. The gun may be angled so that the line of sight out the end of the bore is 37 feet above the target. The bullet doesn't fly on the line of sight of the bore because of gravity. Think of a laser bore sighter... the laser beam isn't affected by gravity but the bullet is. The bullet begins to drop immediately which is why the barrel must be angled so high in order to drop it into the target. I didn't watch all 54 minutes of the video but I suspect a similar misunderstanding is responsible for the 2500 foot comment as well.

And I didn't check the math on either one of these and they may be off, but the comment makes perfect sense if looked at in this way.
 
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The base alone added 390 moa. One Moa at 4.4 is 81”. 390 moa @ 4.4 miles is 26xx feet.

I believe the total MOA was around 800( cant remember what they said. At 4.4 miles the bore line is over a mile high.
 
9600 Inches is 800 ft, so my reference is just shy of that, I did not pull the exact information as I didn't watch the video
So figuring how many Mils they used plus the changes in zeros and offsets, then just convert it

Math is math like noted above, if the base alone is 26ft at that range
 
I gotta do some "mafs" but "drop" won't directly translate into max height. A VERY rough calculation would be about 1/2 your total drop is max elevation. So if you drop is 800 feet, its going to go about 400 feet "up in the air"

Its all about rotated coordinate systems and depature from boresight. (angles are hard yo!). I did a basic (No air resistance) calc and to get to 4000 yards it would go about 90 feet in the air (2800 fps M/V). Air resistance means it actually has to go higher, but that gives you a ballpark--100 to 400 above the ground.
 
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It's more like 66% not 50%...

if you go too the kestrel and look at the TRACE setting, which shows you where to look above the line of sight for your round. If I have a 65.8 MIL Hold on the shot, it shows 43.8 for the TRACE so it's gonna go up that high when trying to look for it.
If you don't have a Kestrel you can do the same in most ballistic calculators by changing the zero setting in that app to the range to target..

Say1000, then look at the trajectory, which normally shows all drop - negative numbers But, with a zero at 1000 yards the trajectory will then show some positive numbers.

The highest point in the trajectory positive numbers will be the highest point over terrain assuming a near zero angle between rifle and target.
 
If you don't have a Kestrel you can do the same in most ballistic calculators by changing the zero setting in that app to the range to target..

Say1000, then look at the trajectory, which normally shows all drop - negative numbers But, with a zero at 1000 yards the trajectory will then show some positive numbers.

The highest point in the trajectory positive numbers will be the highest point over terrain assuming a near zero angle between rifle and target.
That's a cool trick I didn't know.