Re: A question about suppressor noise properties.
here is my angle with about the same conclusions as the above post......
Without going into the different mechanisms in how a suppressor works, I'll guess with the following:
Thermo laws 1 and 2 are a good start.
#1 conservation of energy (it has to be accounted for)
#2 entropy (given the same shit happening over time, it's all going even out)
Energy into the suppressor is:
1) hot gas at velocity
2) the projectile (M & V): BUT the projectile passes through, often with MORE velocity so we can ignore #2.
#1 normally a rifle shot (w/o suppressor) creates a significant blast and report. The suppressor obviously reduces this. In return, the suppressor does not buldge, explode, dig holes, or have any other mechamism to transfer gas velocity energy except to create heat. Conservation of energy is conserved in that the reduced report and blast turns into heat.
Back to thermo law #2:
There likely is a critical temperature where the suppressor itself and the trapped gas inside becomes more equal to or hotter then the new injected gas from firing a bullet, thus greatly reducing it's efficiency or ability to change gas velocity into heat.
This could be a linear change with temp, but the effects are largely unheard with supersonic ammo untill the report greatly exceeds the sonic crack.....But, I doubt it.
A "mental picture" may be that the gas velocity is always lowered mechancially due to the suppressor's volume and the baffles. These features are constants regardless of heat. However, if you ignore that and think about the basics, it makes sense.