• 1 WEEK LEFT: This Target Haunts Me Contest

    Tell us about the one that got away, the flier that ruined your group, the zero that drifted, the shot you still see when you close your eyes. Winner will receive a free scope!

    Join contest

Rifle Scopes First Post with a UNERTL 10x question

Airborne2000

Private
Minuteman
May 15, 2008
2
0
Hey guys, this is my first post but I have been on here a good bit for a few years now just gathering/learning info. My first question is this….

How does the 10x Unertl elevation knob work?

The top part I know is marked in 100 Yard increments to 1000y, but are there 1 MOA adjustments also in between each 100 yard increment marked on the dial?

Like a M3A or do you rely on the vaneer ring to make the necessary ½ MOA adjustments to get on target? So, would you adjust like example 1 or 2?

1. Target is 550 yards away, place the elevation dial on 5+3 (~550 yard setting like a M3A) and fire. Hit. If need to adjust the Vaneer ring to get dead center of target.

2. Or…Target is 550 yards away, set elevation dial on 5 (because it can only be set on “5” or “6”) and adjust the Vaneer ring up 3 MOA to get on target. Hit.



I don’t have one of these scopes and have never seen one in person, I just see pictures often on the internet and have been wondering how they work. I know the Mk4 m3 and M3A really well, but I don’t think the Unertl works the same.


Ok, second question is with the oval mildots, Keep in mind I ask this though as if this is how the Marines would do it at Sniper school. For a fast way to read and dial in would you just read the mils like this:

Size of Target (inches) X 27.77 DIVIDED BY mil reading (ex. 1.45mil) = Distance in yards



This is the way that all the internet tutorials read out:

Size of Target (Yards) X 1000 DIVIDED BY mil reading ( 1 and 7/8mil (in a fraction??))= Distance in Yards


To me the internet tutorial way seems like a hard way to teach a Marine for the main reason for in real life its harder to look at an object and say, “well its about .74 of a yard tall” that’s hard to do, so, “oh its about 34” tall” would seem the more quick and simple way. So I would think that the first formula is what they use and it’s very similar to the Army and AF way of milling on the M3A.

Can anyone shed some light on this info for me, if you are/ former MOS 0317 it would really help.

Thanks guys.
 
Re: First Post with a UNERTL 10x question

<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Airborne2000</div><div class="ubbcode-body"> The top part I know is marked in 100 Yard increments to 1000y, but are there 1 MOA adjustments also in between each 100 yard increment marked on the dial? </div></div>
No, there are not any "clicks" between yardage marks, it is a smooth transition between the numbers with a solid click at each yardage mark.

<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Airborne2000</div><div class="ubbcode-body">Like a M3A or do you rely on the vaneer ring to make the necessary ½ MOA adjustments to get on target? So, would you adjust like example 1 or 2?

1. Target is 550 yards away, place the elevation dial on 5+3 (~550 yard setting like a M3A) and fire. Hit. If need to adjust the Vaneer ring to get dead center of target.

2. Or…Target is 550 yards away, set elevation dial on 5 (because it can only be set on “5” or “6”) and adjust the Vaneer ring up 3 MOA to get on target. Hit. </div></div>

The fine adjustment knob is used like you are saying for a distance between even 100 yard increments with the + or - numbers being equal to 1 MOA. So you can either go to 5 and work your way up or to 6 and work your way down. However, you can also turn the elevation knob to the space between 5 and 6 and hold center mass for a 550 yard shot. There is not a detent here and it may move, but it will work.

The fine adjustment knob is also used for variations in environmental factors and ammunition lots without having to re-zero.

<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Airborne2000</div><div class="ubbcode-body">Size of Target (inches) X 27.77 DIVIDED BY mil reading (ex. 1.45mil) = Distance in yards

This is the way that all the internet tutorials read out:

Size of Target (Yards) X 1000 DIVIDED BY mil reading ( 1 and 7/8mil (in a fraction??))= Distance in Yards</div></div>

The textbook answer would be that the mil relation formula is (or was in the 1990's) first taught as: Size of Target in Yards x 1000 is divided by the Size of the Target in Mils = Range in Yards.

However, once you have that basic understanding, you begin to fine tune your estimation of both the target size and mil reading - be it in yards/inches and .25/.125 mil (1/4 or 1/8). So eventually you would learn both the yards and inches formula and then you apply whichever formula you need based on the object/objects being milled.

It is all about actually practicing these things, it isn't something that once you learn you just do, you need to continually work at it to maintain/improve your abilities be it range estimation or any of the other skills.
 
Re: First Post with a UNERTL 10x question

Thanks Tim thats what I was looking for.

I have one more question if you can answer this, At Marine Scout Sniper school what is the standard size target they use? is it the E-type, 40" tall / 1.1 yards tall?