Minute of Angle on the MOON!!!

AMG04

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Minuteman
Jan 26, 2012
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Fort Worth, TX
Took a few shots through the spotting scope this evening. Impacts (in Mils) - Left 1.4, High 0.1 and again at Right 2.0, Down 2.0.

LOL
 

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please IN THIS FORUM WE OBEY THE LAWS OF PHYSICS.

If you were on the moon and shot your gun the bullet would circle the moon and hit you in the back of your head.

Gravity still in effect on the moon. Your bullet still drops.

You would have to fire your rifle at or above the orbital velocity of the moon. Assuming it is a perfect sphere.

Which it isn't

In fact even low moon orbits are not particularly stable because the moon is in fact not a particularly good sphere.

But lets do the math because we don't call it rocket science for nothing

v = Sqrt(GM/R)
G = Gravitational Constant
M = mass moon
R is radius of your orbit (for our purpose, I will use the mean radius of the moon plus 1 meter because apparently Frank is on the moon--it really wont make that much difference but I wanted to make a short joke)

R = 1737000 meters so yeah, that 1 ain't gonna matter
G = 6.67E -11 (in SI)
M = 7.346E22 kg

turns out to be 5600 feet per second (give or take)

So no, it will not hit you in the back of the head unless you get it going A LOT faster than you do on the earth (2X or more). And somehow hit a perfect orbit that cancels out all the mass plutons on the moon (which you won't).

BUT MY GUN WILL FIRE FASTER BECAUSE NO AIR RESISTANCE!

Not twice as fast. Air resistance is not that strong.

edit:

Pics and everything.
 
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At a class I attended we were doing ranging exercises at night. I decided to see if I could determine the size of the moon with my mil retical. I was within 1% according to what Google says it is. Fun little exercise.