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Rifle Scopes new to ranging

mdmp5

Gunny Sergeant
Full Member
Minuteman
  • May 7, 2009
    5,086
    2,507
    Through all these years of shooting at ranges 300 yards or less, I never had to utilize the reticles for ranging. I have had some down time over the last few weeks, so I decided that it was time to learn. I started using the long range shooting sim, and I kind of got the hang of it for the most part.

    I do have an issue though. When the wind is at an angle, the sim says to use the sine function to calculate the true horizontal component of the wind. This is counterintuitive to me; using the sine function seems to calculate the y-component of the wind, not the x-component. In my reasoning, I figured that the cosine function would be correct to use, but the values yielded do do correspond to correct adjustments in the sim.

    Am I missing something, and is my logic completely ass backwards?
     
    Re: new to ranging

    Never mind, I think I just got it: the y-component is actually the x-component. 1:30 and 4:30 are 45 degrees, and the both the cosine and sine are 0.5. It is all about how you measure your angles, so you could use the sine of 60 or the cosine of 30 to yield the same value. Sorry about the mix up.
     
    Re: new to ranging

    <div class="ubbcode-block"><div class="ubbcode-header">Quote:</div><div class="ubbcode-body">...1:30 and 4:30 are 45 degrees, and the both the cosine and sine are 0.5.</div></div>

    Umm, no. The sine and cosine of 45 degrees are both 0.707

    If what you are seeking is the crosswind value, multiply the wind value by the sine of the angle to the line of fire, with the line of fire as zero.

    For example, a full-value crosswind from the right is 90 degrees to the line of fire, and the sin of 90 degrees is 1.00.
     
    Re: new to ranging

    Yes, my mistake, the sine and cosine of 45 is 0.707. The cosine of 60 is 0.5 and the sine of 30 is 0.5, which is what I meant to say.