Wind problem episode 277

Adkhunter3

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Jun 16, 2020
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I think i get the math he did, just subbed .5 for .6 to make the math a little quicker. Where is the +/- .3 coming from? and where did you get 5th bracket from?
 

Hawkguy29

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Apr 29, 2018
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+/- .3 comes from the “wind budget” or room for error for the size plate if you hold center.

As far as the bracket goes for his gun (5mph gun) at 500m the first bracket is .5 for 5mph wind, 2nd bracket 1.0mil for 10mph, 3rd bracket 1.5mils 15mph wind, 4th-2.0mils for 20mph wind and finally 5th bracket will be 2.5mils for 25mph wind.

Correct me if I’m wrong here.
 

Skookum

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  • May 6, 2017
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    I think i get the math he did, just subbed .5 for .6 to make the math a little quicker. Where is the +/- .3 coming from? and where did you get 5th bracket from?
    No. The 0.5 comes from the range which is 500 yards.

    The 5th bracket comes from a 5mph gun in a 25mph wind. 25/5=5.

    The 0.3 comes from the target being 0.6 wide and therefore 0.3 from center to edge.
     

    Shootnwrench

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    Feb 25, 2020
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    Soldotna AK
    Problem
    .6mil target @ 500yds, 25mph wind

    Solving for
    .308 175smk = 4mph gun

    25mph/4mph = 6.25
    6.25 x .5 = 3.125 Or call it 3.1 Mil correction

    Solving for
    6.5C 140’s = 6mph gun

    25mph/6mph = 4.166
    4.166 x .5 = 2.08 or call it 2.1 Mil correction
     

    Leatherlunger

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    Feb 17, 2012
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    These podcasts got me thinking it would be nice to have a wind budget chart on my “sheet” to understand my wiggle room for various sized targets at different yardages. I havent tried it out yet so well see how it goes next time im at the range. In theory you could use it to determine hit probability for max and min wind speeds. Again havent tried it out yet, see how it goes. Its the red column on the far right.
    82CE4CE2-97B2-4279-9E41-6FAC0AFF0BC1.png
     

    Leatherlunger

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    Feb 17, 2012
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    So looking at the chart in red at 700 yards. i could be off a little less than 2mph on a 9” target, a little less than 4mph on an 18” target and little less than 8mph on a 36” target for my wind read accuracy. Btw this is based on a 4 mph rifle at my home DA. In my dumb brain this would potentially get a touch on target as long as my verticle was good and my inital wind estimation was good. Again i think this is right based on listening to the podcast but we will see
     

    Leatherlunger

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    Feb 17, 2012
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    Although thinking about it now should the error budget be the full width of a given target size or half of it? 🙃
     

    Hawkguy29

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    Apr 29, 2018
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    Although thinking about it now should the error budget be the full width of a given target size or half of it? 🙃
    Well if you want a center hit then it would be half the size. However if you just want a hit, hold the upwind edge of plate and you have a few more mph of wind (budget) to play with. But the right answer is half the width for a center hit.
     
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    lowlight

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    You really don't have time to play with error size,

    You assume you can hit the target, so if you have a .5 plate and can put a .3 and .6 hold on it, you do that... and not worry about your miss, cause there is always potential to miss
     
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    Leatherlunger

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    Copy that Frank. I guess by playing with the error budget concept on a table, at least it gained me some perspective on probability for varying ranges if I misjudged the wind. Its been neat to learn about all this stuff thank you.