Re: Dimensions of scope base?
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Rafael</div><div class="ubbcode-body">Yeah, Math was once my strong subject....about a million years ago. Now I need to be led.
In the end, his statement looks good to me: "... 0.01745" moved per degree, per inch!"
The length of the base doesn't matter, only the variation in angle between any two points you choose as reference points along the length when you set up to cut.
So....
If you set up the base measuring height differential between two points that are 4" apart, 1 full degree would be 4 x .1745 equals .0698".
So, a .0698" differential in height across 4" would be 1 degree.
15MOA is 1/4 of a degree, so one quarter of .0698" is .01745".
If you set up the work referencing two points 4" apart, and one point is .01745" higher or lower than the other, you will arrive at 15MOA. It does not matter if the base is 4" long or 20" long; so long as the two reference points are 4" apart and you create a .01745" differential between the two, it should be 15 MOA.
I hope someone will chime in if they spots mistakes in my thinking. </div></div>
So if my base was 6" long I could multiply 6 x .1745 getting 1.047. Then find that a quarter of that is .26175?
What dad and I were thinking is placing a shim of the correct thickness under one end and milling flat across giving a slant of 15moa.
We have made many scope bases that were flat- no elevation built in, for Ruger MkII pistols. This will be our first with elevation.
I haven't decided to build it. There may be some parts that would be too difficult to mill, but it might be fun to try.
Jim
