Last updated at Dec. 24, 2019 by Teachoo

Transcript

Example 10 If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A. Given that, sin 3A = cos (A – 26°) cos (90° – 3A) = cos (A − 26°) Comparing angles 90 – 3A = A − 26° − 3A – A = – 26 – 90 − 4A = − 116 A = (−116)/(−4) A = 29 Hence, A = 29°

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Example 9 Deleted for CBSE Board 2022 Exams

Example 10 Important Deleted for CBSE Board 2022 Exams You are here

Example 11 Important Deleted for CBSE Board 2022 Exams

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Chapter 8 Class 10 Introduction to Trignometry (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.